((n^2)/(n/2))-(2/n*n)=3

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Solution for ((n^2)/(n/2))-(2/n*n)=3 equation: 


D( n )

n = 0

n/2 = 0

n = 0

n = 0

n/2 = 0

n/2 = 0

1/2*n = 0 // : 1/2

n = 0

n in (-oo:0) U (0:+oo)

(n^2)/(n/2)-((2/n)*n) = 3 // - 3

(n^2)/(n/2)-((2/n)*n)-3 = 0

(n^2)/(n/2)-3-2 = 0

2*n-5 = 0 // + 5

2*n = 5 // : 2

n = 5/2

n = 5/2

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